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## Homework Statement

A falling stone takes 0.28s to travel past a window 2.2m tall. From what height above the top of the window did the stone fall?

## The Attempt at a Solution

Vo=?, the velocity at the top of the window

a= -9.8m/s^2

t=.28s

d=2.2m

v=?

Vo=(1/2at^2-d)/-t

[1/2(-9.8)(.28)^2-2.2]/-.28=9.2m/s

Vo now becomes V although it still represents the velocity at the top of the window.

t=?

d=?

a=9.8 m/s^2

Vo=0

V=9.2m/s

Solve for "D"

D=(V^2-Vo^2)/2a

(9.2^2 - 0)/ (2*-9.8)= -4.3m

The ball is dropped from 4.3m.

Am I right?

Thanks,

Joe