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f1=250 lb @ 60 degrees from x

f2= 375 lb @ -45 degrees from x

Ok I got the magnitude by doing this:

(360-2(255))/2=-75 degrees

fr=sqroot of (250^2+375^2-2(250)(375)cos(75)

fr=393.188~ 393

then I got the angle by this:

375/sin x = 393.188/sin 75

x=67.1088

how do i get the resultant angle, what do I need to add to the 67 degrees?